On halogenation,an alkane gives only one mono | vedclass

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(D) For an alkane to give only one monohalogenated product,all hydrogen atoms in the molecule must be equivalent.$1$. $2-$methylbutane has different t

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both $(b)$ and $(c)$

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(D) For an alkane to give only one monohalogenated product,all hydrogen atoms in the molecule must be equivalent.$1$. $2-$methylbutane has different types of hydrogen atoms,leading to multiple monohalogenated products.$2$. $2,2-$dimethylpropane (neopentane) has $12$ equivalent hydrogen atoms attached to the four equivalent methyl groups. Thus,it gives only one monohalogenated product.$3$. Cyclopentane has $10$ equivalent hydrogen atoms in a cyclic structure. Thus,it also gives only one monohalogenated product.Therefore,both $(b)$ and $(c)$ are correct.

On halogenation,an alkane gives only one monohalogenated product. The alkane may be

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